Forum:Crit Mechanics

I'm trying to figure out how the damage for a Critical and Sneak Attack Critical is calculated. I think I have it down, but I'd like to get confirmation.

1. A regular Critical Hit does not multiply damage in any way; instead, it adds the Critical Damage to the weapon's Base Damage. So a Critical Hit with the Dart Gun would do 6 Base +12 Critical Damage, for a grand total of 18 damage on a Critical Hit.

2. Only when a hit is a Sneak Attack Critical is the damage multiplied; specifically, by 2. So a Critical Hit with the Dart Gun does (6+12)*2=36 damage.

3. Weapons with multiple projectiles (such as the Metal Blaster) divide their Base Damage between each projectile (technically, 'projectile' is the wrong term for a laser weapon, but we'll go with it). The Metal Blaster's 55 damage is divided by 9, so each projectile does 6.1 damage (the 1 repeats ad infinitum, so we'll stick with 6.1). When firing outside of VATS, each projectile gets a chance to crit. If it does, that projectile does 33.1 damage. If all projectiles crit, then we get 297 total damage.

4. A Sneak Attack Critical with the Metal Blaster would guarantee that each projectile would crit, and also multiply the damage of each by 2. So we get 33.1*2=66.2 damage a projectile. Multiply that by 9 projectiles, and we would get 595.8 damage done with the Sneak Attack Crit.

Do I have that correctly? Swk3000 04:43, November 27, 2010 (UTC)